Exercise 1.Given the following piece of code

 

int i = 10;   

char c= 'A';

double f = 25.5;

int *iptr = &i;

char *cptr = &c;

 

 You are expected to display the result of following statements in the given format.

 

 

Value of i	Address of i	Value of iptr	Address of iptr	Derefrenced Value of *iptr	Size of iptr	Size of i
Value of c	Address of c	Value of cptr	Address of cptr	Derefrenced Value of *cptr	Size of cptr	Size of c

Note:   The format specifier for displaying address of any data item is %x

 

 

 

 

SOURCE CODE:

#include<stdio.h>
void header()
{
  printf("\n\n\n\t\tBuilt & Designed by Arslan Malik\n\n\t\t www.CWorldbyAS.blogspot.com\n\n\n");
}
int main()
{
    int i=10;
    char c='A';
    double f=25.5;
    int *iptr=&i;
    char *cptr=&c;
    header();
    printf("\n\n\n\n\n\n");
    system("pause");
    system("cls");
    printf("Value of i\tAddress of i\tValue of iptr\tAddress of iptr\t");
    printf("\n\n    %d\t\t  %p\t   %d\t   %p  ",i,&i,iptr,&iptr);
    printf("\n\nDereferenced value of *iptr\tSize of iptr\tSize of i");
    printf("\n\n\t  %d\t\t\t     %d\t           %d",*iptr,sizeof(iptr),sizeof(i));
    printf("\n\n");
    printf("Value of c\tAddress of c\tValue of cptr\tAddress of cptr\t");
    printf("\n\n    %c\t\t  %p\t   %d\t   %p  ",c,&c,cptr,&cptr);
    printf("\n\nDereferenced value of *cptr\tSize of cptr\tSize of c");
    printf("\n\n\t  %c\t\t\t     %d\t           %d",*cptr,sizeof(cptr),sizeof(c));
    printf("\n\n");
    return 0;
}